Teaching Lab 2019-2020 Report

Breakdown by Content Knowledge

Some text here.

ELA Table

ELA Question Key

Math Question Key

ELA text here.

Matched Analysis

This analysis only compares data for which respondents completed at least 75% of the responses in both the diagnosis and follow-up questionnaires, providing a matched sample analysis table that can be used to gauge improvement on an individual basis.

ELA Table Matched and Grouped

There were no matched samples in 2019-2020 for District 11.

Improvements

Matched Improvements

In this section the overall improvement of only matched emails are investigated, to show how specific respondents responses changed from the start to the finish of their professional learning.

ELA Percent that did Improve

## # A tibble: 1 × 1
##   `100 * sum(final_score > 0, na.rm = T)/n()`
##                                         <dbl>
## 1                                           0
## # A tibble: 1 × 1
##   `100 * sum(final_score > 0, na.rm = T)/n()`
##                                         <dbl>
## 1                                         NaN
100 * sum(final_score > 0, na.rm = T)/n()
NaN
100 * sum(final_score > 0, na.rm = T)/n()
NaN
100 * sum(final_score > 0, na.rm = T)/n()
NaN
100 * sum(final_score > 0, na.rm = T)/n()
NaN

Math Percent that Did Improve

Overall

ELA

Here’s what ELA looks like by question:

Mindsets and expectations

Question Fall n1 Spring n2 Improvement
1 NaN 0 NaN 0 NaN
2 NaN 0 NaN 0 NaN
3 100 4 100 4 0
4 100 4 100 4 0
5 NaN 0 NaN 0 NaN
6 NaN 0 NaN 0 NaN
7 0 4 0 4 0
8 75 4 75 4 0
9 75 4 50 4 -25
sum(increase1, na.rm = T)/118 sum(increase2, na.rm = T)/118 sum(increase3, na.rm = T)/141 sum(increase4, na.rm = T)/141 sum(increase5, na.rm = T)/118 sum(increase6, na.rm = T)/118 sum(increase7, na.rm = T)/141 sum(increase8, na.rm = T)/141 sum(increase9, na.rm = T)/141
0 0 2.836879 2.836879 0 0 0 2.12766 1.41844
Question Fall n1 Spring n2 Improvement
1 100 4 66.66667 3 -33.333333
2 75 4 66.66667 3 -8.333333
3 0 4 66.66667 3 66.666667
4 50 4 66.66667 3 16.666667
sum(increase35, na.rm = T)/100 sum(increase36, na.rm = T)/100 sum(increase37, na.rm = T)/100 sum(increase38, na.rm = T)/100
0.02 0.02 0.02 0.02
Question Fall n1 Spring n2 Improvement
1 100 3 100 4 0
2 0 3 50 4 50
3 75 4 100 4 25
sum(increase39, na.rm = T)/97 sum(increase40, na.rm = T)/97 sum(increase41, na.rm = T)/97
0.03092784 0.01030928 0.03092784
Question Fall n1 Spring n2 Improvement
1 NaN 0 NaN 0 NaN
2 NaN 0 NaN 0 NaN
3 NaN 0 NaN 0 NaN
sum(increase42, na.rm = T)/10 sum(increase43, na.rm = T)/10 sum(increase44, na.rm = T)/10
0 0 0
Question Fall n1 Spring n2 Improvement
1 0 712 0 712 0
2 0 712 0 712 0
3 0 712 0 712 0
4 0 712 0 712 0
5 0 712 0 712 0
6 0 712 0 712 0
7 0 712 0 712 0
sum(increase45a, na.rm = T)/47 sum(increase45b, na.rm = T)/47 sum(increase45c, na.rm = T)/47 sum(increase45d, na.rm = T)/47 sum(increase45e, na.rm = T)/47 sum(increase45f, na.rm = T)/47 sum(increase45g, na.rm = T)/47
0 0 0 0 0 0 0
Question Fall n1 Spring n2 Improvement
1 NaN 0 NaN 0 NaN
2 NaN 0 NaN 0 NaN
3 NaN 0 NaN 0 NaN
4 NaN 0 NaN 0 NaN
5 NaN 0 NaN 0 NaN
6 NaN 0 NaN 0 NaN
sum(increase46a, na.rm = T)/143 sum(increase46b, na.rm = T)/143 sum(increase46c, na.rm = T)/143 sum(increase46d, na.rm = T)/143 sum(increase46e, na.rm = T)/143 sum(increase46f, na.rm = T)/143
0 0 0 0 0 0
Question Fall n1 Spring n2 Improvement
47 NaN 0 NaN 0 NaN
48 NaN 0 NaN 0 NaN
49 NaN 0 NaN 0 NaN
50 NaN 0 NaN 0 NaN
51 NaN 0 NaN 0 NaN
52 NaN 0 NaN 0 NaN
## [1] NaN
sum(increase47, na.rm = T)/sum(!is.na(increase47)) sum(increase48, na.rm = T)/sum(!is.na(increase48)) sum(increase49, na.rm = T)/sum(!is.na(increase49)) sum(increase50, na.rm = T)/sum(!is.na(increase50)) sum(increase51, na.rm = T)/sum(!is.na(increase51)) sum(increase52, na.rm = T)/sum(!is.na(increase52))
NaN NaN NaN NaN NaN NaN
 

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