Breakdown by Content Knowledge

Some text here.

ELA Table

ELA Question Key

Math Question Key

ELA text here.

Matched Analysis

This analysis only compares data for which respondents completed at least 75% of the responses in both the diagnosis and follow-up questionnaires, providing a matched sample analysis table that can be used to gauge improvement on an individual basis.

ELA Table Matched and Grouped

There were no matched samples in 2019-2020 for District 11.

Improvements

Matched Improvements

In this section the overall improvement of only matched emails are investigated, to show how specific respondents responses changed from the start to the finish of their professional learning.

ELA Percent that did Improve

## # A tibble: 1 × 1
##   `100 * sum(final_score > 0, na.rm = T)/n()`
##                                         <dbl>
## 1                                           0

## # A tibble: 1 × 1
##   `100 * sum(final_score > 0, na.rm = T)/n()`
##                                         <dbl>
## 1                                         NaN

100 * sum(final_score > 0, na.rm = T)/n()
NaN

100 * sum(final_score > 0, na.rm = T)/n()
NaN

100 * sum(final_score > 0, na.rm = T)/n()
NaN

100 * sum(final_score > 0, na.rm = T)/n()
NaN

Math Percent that Did Improve

Overall

ELA

Here’s what ELA looks like by question:

Mindsets and expectations

Question	Fall	n1	Spring	n2	Improvement
1	NaN	0	NaN	0	NaN
2	NaN	0	NaN	0	NaN
3	100	4	100	4	0
4	100	4	100	4	0
5	NaN	0	NaN	0	NaN
6	NaN	0	NaN	0	NaN
7	0	4	0	4	0
8	75	4	75	4	0
9	75	4	50	4	-25

sum(increase1, na.rm = T)/118	sum(increase2, na.rm = T)/118	sum(increase3, na.rm = T)/141	sum(increase4, na.rm = T)/141	sum(increase5, na.rm = T)/118	sum(increase6, na.rm = T)/118	sum(increase7, na.rm = T)/141	sum(increase8, na.rm = T)/141	sum(increase9, na.rm = T)/141
0	0	2.836879	2.836879	0	0	0	2.12766	1.41844

Question	Fall	n1	Spring	n2	Improvement
1	100	4	66.66667	3	-33.333333
2	75	4	66.66667	3	-8.333333
3	0	4	66.66667	3	66.666667
4	50	4	66.66667	3	16.666667

sum(increase35, na.rm = T)/100	sum(increase36, na.rm = T)/100	sum(increase37, na.rm = T)/100	sum(increase38, na.rm = T)/100
0.02	0.02	0.02	0.02

Question	Fall	n1	Spring	n2	Improvement
1	100	3	100	4	0
2	0	3	50	4	50
3	75	4	100	4	25

sum(increase39, na.rm = T)/97	sum(increase40, na.rm = T)/97	sum(increase41, na.rm = T)/97
0.03092784	0.01030928	0.03092784

Question	Fall	Spring	Improvement
1	NaN	NaN	NaN
2	NaN	NaN	NaN
3	NaN	NaN	NaN

sum(increase42, na.rm = T)/10	sum(increase43, na.rm = T)/10	sum(increase44, na.rm = T)/10
0	0	0

Question	n1	n2
1	712	712
2	712	712
3	712	712
4	712	712
5	712	712
6	712	712
7	712	712

sum(increase45a, na.rm = T)/47	sum(increase45b, na.rm = T)/47	sum(increase45c, na.rm = T)/47	sum(increase45d, na.rm = T)/47	sum(increase45e, na.rm = T)/47	sum(increase45f, na.rm = T)/47	sum(increase45g, na.rm = T)/47
0	0	0	0	0	0	0

Question	Fall	Spring	Improvement
1	NaN	NaN	NaN
2	NaN	NaN	NaN
3	NaN	NaN	NaN
4	NaN	NaN	NaN
5	NaN	NaN	NaN
6	NaN	NaN	NaN

sum(increase46a, na.rm = T)/143	sum(increase46b, na.rm = T)/143	sum(increase46c, na.rm = T)/143	sum(increase46d, na.rm = T)/143	sum(increase46e, na.rm = T)/143	sum(increase46f, na.rm = T)/143
0	0	0	0	0	0

Question	Fall	Spring	Improvement
47	NaN	NaN	NaN
48	NaN	NaN	NaN
49	NaN	NaN	NaN
50	NaN	NaN	NaN
51	NaN	NaN	NaN
52	NaN	NaN	NaN

## [1] NaN

sum(increase47, na.rm = T)/sum(!is.na(increase47))	sum(increase48, na.rm = T)/sum(!is.na(increase48))	sum(increase49, na.rm = T)/sum(!is.na(increase49))	sum(increase50, na.rm = T)/sum(!is.na(increase50))	sum(increase51, na.rm = T)/sum(!is.na(increase51))	sum(increase52, na.rm = T)/sum(!is.na(increase52))
NaN	NaN	NaN	NaN	NaN	NaN

Teaching Lab 2019-2020 Report